2.3-Meter-Wide Container House
A 2.3-meter-wide container house, if its length and height are also common dimensions (such as a length of 5.9 meters and a height of 2.3 meters), can accommodate a maximum of 72 cubic wooden boxes with an edge length of 0.7 meters when filled. Here is a detailed analysis:
Method for Calculating the Number of Accommodated Wooden Boxes
To calculate the maximum number of cubic wooden boxes that a rectangular container can hold, it is necessary to calculate the number of wooden boxes that can be placed in the length, width, and height directions of the container respectively, and then multiply these three numbers to obtain the total accommodation capacity. The calculation formula is: Total accommodation capacity = Number of wooden boxes in the length direction × Number of wooden boxes in the width direction × Number of wooden boxes in the height direction. When calculating the number of wooden boxes that can be placed in each direction, divide the length of the container in that direction by the edge length of the cubic wooden box. The quotient is the number of wooden boxes that can be placed, and the remainder is discarded because it cannot accommodate a complete wooden box.
Specific Calculation Process
Assume that the container has a length of 5.9 meters, a width of 2.3 meters, and a height of 2.3 meters, and the cubic wooden box has an edge length of 0.7 meters.
- Length direction: $5.9\div0.7 = 8$ (boxes)... $0.3$ (meters). This means that a maximum of 8 wooden boxes can be placed along the length direction.
- Width direction: $2.3\div0.7 = 3$ (boxes)... $0.2$ (meters). That is, a maximum of 3 wooden boxes can be placed along the width.
- Height direction: $2.3\div0.7 = 3$ (boxes)... $0.2$ (meters). This indicates that a maximum of 3 wooden boxes can be placed along the height.
By multiplying the number of wooden boxes that can be placed in the three directions, the total accommodation capacity is obtained as: $8\times3\times3 = 72$ (boxes)
